SQL Server : count date with biweekly date -

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i having trouble count items biweekly (end @ friday)

table like:

+------------+------------+ | itemnumber |    date    | +------------+------------+ |        235 | 2016-03-02 | |        456 | 2016-03-04 | |        454 | 2016-03-08 | |        785 | 2016-03-10 | |        123 | 2016-03-15 | |        543 | 2016-03-18 | |        863 | 2016-03-20 | |        156 | 2016-03-26 | +------------+------------+

result:

+-------+------------+ | total |   biweek   | +-------+------------+ |     4 | 2016-03-11 | |     3 | 2016-03-25 | |     1 | 2016-04-08 | +-------+------------+

if understood problem correctly, should work:

select    sum(1),    dateadd(day, ceiling(datediff(day,4, [date]) / 14.0) * 14, 4)    yourtable group    dateadd(day, ceiling(datediff(day,4, [date]) / 14.0) * 14, 4)

this calculates date difference in days "day 4" aka. 5.1.1900, divides 14 (rounding up) , multiplies 14 biweeks , adds "day 4".


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