javascript - Achieve this outcome without the use of Modernizr? -

-

for reasons i'd rather not into. trying achieve effects of menu :

demo : http://tympanus.net/codrops/2013/04/19/responsive-multi-level-menu/

but without use of modernizr possibly using jquery in place. part of code tripping me :

$.dlmenu.prototype = {     _init : function( options ) { // options         this.options = $.extend( true, {}, $.dlmenu.defaults, options );         // cache elements , initialize variables         this._config();          var animendeventnames = {                 'webkitanimation' : 'webkitanimationend',                 'oanimation' : 'oanimationend',                 'msanimation' : 'msanimationend',                 'animation' : 'animationend'             },             transendeventnames = {                 'webkittransition' : 'webkittransitionend',                 'moztransition' : 'transitionend',                 'otransition' : 'otransitionend',                 'mstransition' : 'mstransitionend',                 'transition' : 'transitionend'             };         // animation end event name         this.animendeventname = animendeventnames[ modernizr.prefixed( 'animation' ) ] + '.dlmenu';         // transition end event name         this.transendeventname = transendeventnames[ modernizr.prefixed( 'transition' ) ] + '.dlmenu';         // support css animations , css transitions         this.supportanimations = modernizr.cssanimations;         this.supporttransitions = modernizr.csstransitions;          this._initevents();      },

codepen - http://codepen.io/eclipsewebdesign/pen/fcugj/

possible? appreciated tried using jquery limited knowledge not successful.

thank you

$('.top-menu').click(function() {     $(this).fadein('fast', function() {         if($(this).next().length > 0) {             $(this).fadeout('fast', function() {                 $(this).next().fadein('fast');         });         }     }); });

something this?


Comments

Post a Comment

Popular posts from this blog

Django REST Framework perform_create: You cannot call `.save()` after accessing `serializer.data` -

-
i have following viewset: class artistprofileviewset(viewsets.modelviewset): queryset = artistprofile.objects.all() serializer_class = artistprofileserializer def perform_create(self, serializer): if serializer.is_valid(): serializer.save() with following serializers: class simpleartisttrackserializer(serializers.hyperlinkedmodelserializer): class meta: model = artisttrack fields = (...my fields...) class artistprofileserializer(serializers.hyperlinkedmodelserializer): owners = userserializer(many=true, required=false) tracks = simpleartisttrackserializer(many=true, required=false) class meta: model = artistprofile fields = (...my fields...) i getting following error: assertionerror: cannot call `.save()` after accessing `serializer.data`.if need access data before committing database inspect 'serializer.validated_data' instead. i don't see editing serializer.data object. th...
Read more

Why does Go error when trying to marshal this JSON? -

-
i'm trying rather simple example of trying decode json file structs using golang. however, when attempting error that json: cannot unmarshal object go value of type []main.track which don't understand. here's code in question, , json can found here . package main import ( "encoding/json" "fmt" "net/http" "os" ) // tracks group of track types type tracks struct { tracks []track } // track represents singular track type track struct { name string url string artist artist } // artist represents single artist type artist struct { name string mbid string url string } func main() { url := "http://ws.audioscrobbler.com/2.0/?method=geo.gettoptracks&api_key=c1572082105bd40d247836b5c1819623&format=json&country=netherlands" response, err := http.get(url) if err != nil { fmt.printf("%s\n", err) os.exit(1) } de...
Read more