php - Can I continue coding if ($a[undefined]) as false? -

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i wonder code has security risk or etc?

this code cause notice error.

<?php $array = array(); if ($array['hoge']) { } ?>

and set ~e_notice in php.ini.

should use empty()?

thank you.

the notice error caused because checking if $array['hoge'] either true or false, when in fact value isn't set. correct way code previous if conditional be:

<?php $array = array(); if !empty($array['hoge']) {   //...code executed inside conditional... } ?>

it practice check if array both set , if it's not empty. hope helps! :)


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