coldfusion - Styling a cfcontent which produced an excel sheet with an external stylesheet -

-

i trying incorporate stylesheet cfcontent tag produce excel spreadsheet shown below. however, stylesheet ignored when linked explicit reference. ensure excel spreadsheet incorporate stylesheet?

<cfsetting enablecfoutputonly="yes"> <cfsavecontent variable="stest">     <cfoutput>         <head>             <meta http-equiv="content-type" content="text/html; charset=utf-8" />               <link rel="stylesheet" type="text/css" href="www.somesite.com/bootstrap/another.css" media="all">             <link rel="stylesheet" type="text/css" href="../cssbootstrap/css/another.css" media="all">         </head>         <body>              <cfinclude template="../reports/reportexportedasexcel.cfm">         </body>     </cfoutput> </cfsavecontent> <cfcontent type="application/vnd.ms-excel"> <cfheader name="content-disposition" value="attachment; filename=filename#dateformat(now(),"mmdd")#-#timeformat(now(),"hhmmss")#.xls">   <cfoutput>     <html>           </head>     <body>         #stest#     </body>     </html> </cfoutput>  </cfcontent>

include protocol in link style sheet. <link rel="stylesheet" type="text/css" href="http://www.somesite.com/bootstrap/another.css" media="all">

another option include style sheet content xls file. 

<cfset cssfilepath = getdirectoryfrompath(gettemplatepath()) & "../cssbootstrap/css/another.css" /> <cfset csscontent = fileread(cssfilepath) /> </cfscript> <html>     <cfoutput>         <head>             <style>#csscontent#</style>         </head>     </cfoutput>

Comments

Post a Comment

Popular posts from this blog

Django REST Framework perform_create: You cannot call `.save()` after accessing `serializer.data` -

-
i have following viewset: class artistprofileviewset(viewsets.modelviewset): queryset = artistprofile.objects.all() serializer_class = artistprofileserializer def perform_create(self, serializer): if serializer.is_valid(): serializer.save() with following serializers: class simpleartisttrackserializer(serializers.hyperlinkedmodelserializer): class meta: model = artisttrack fields = (...my fields...) class artistprofileserializer(serializers.hyperlinkedmodelserializer): owners = userserializer(many=true, required=false) tracks = simpleartisttrackserializer(many=true, required=false) class meta: model = artistprofile fields = (...my fields...) i getting following error: assertionerror: cannot call `.save()` after accessing `serializer.data`.if need access data before committing database inspect 'serializer.validated_data' instead. i don't see editing serializer.data object. th...
Read more

Why does Go error when trying to marshal this JSON? -

-
i'm trying rather simple example of trying decode json file structs using golang. however, when attempting error that json: cannot unmarshal object go value of type []main.track which don't understand. here's code in question, , json can found here . package main import ( "encoding/json" "fmt" "net/http" "os" ) // tracks group of track types type tracks struct { tracks []track } // track represents singular track type track struct { name string url string artist artist } // artist represents single artist type artist struct { name string mbid string url string } func main() { url := "http://ws.audioscrobbler.com/2.0/?method=geo.gettoptracks&api_key=c1572082105bd40d247836b5c1819623&format=json&country=netherlands" response, err := http.get(url) if err != nil { fmt.printf("%s\n", err) os.exit(1) } de...
Read more