regex - SQL Regular expression to split a column (string) to multiple rows based on delimiter '/n' -

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i have split column multiple rows. column stores string, , have split delimiter based on '/n'

have written below query. not able specify ^[/n]. other 'n' in string getting removed. please parse string

with sample  ( select 101 id,          'name' test,          '3243243242342342/n12131212312/n123131232/n' attribute_1,          'test value/nneenu not/nhoney' attribute_2    dual  )  -- end of sample data select id,        test,        regexp_substr(attribute_1,'[^/n]+', 1, column_value),        regexp_substr(attribute_2,'[^/]+', 1, column_value)   sample,        table(          cast(            multiset(select level                         dual                       connect level <= length(attribute_1) - length(replace(attribute_1, '/n')) + 1                    ) sys.odcinumberlist          )        )  regexp_substr(attribute_1,'[^/n]+', 1, column_value) not null /

you need use class [[:cntrl:]] , '[^/n]+' not syntactically either.

the escape char '\' , cannot use [] "wrap" special chars, need use () instead.(that grouping)

if want ignore cr (e.g.'\n') , use [^[:cntrl:]] in sec param in regexp_substr

more help: http://psoug.org/snippet/regular-expressions--regexp-cheat-sheet_856.htm


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