c++ - Operator Overloading -

i'm confused topic regarding operator overloading. see following code:

#include <iostream>;  class vectors { public:     int x, y;     vectors() {};     vectors(int a,int b) {         x = a, y = b;     }     vectors operator+(vectors aso) {         vectors brandnew;         std::cout << "aso x " << aso.x << std::endl;         std::cout << "aso y " << aso.y << std::endl;         brandnew.x = brandnew.x + aso.x;         brandnew.y = brandnew.y + aso.y;         return (brandnew);     }; }; int main() {     vectors v1(2,3);     vectors v2(4,5);     vectors v3;     v3 = v1 + v2;      std::cout << "vector v3 x : " << v3.x << std::endl;     std::cout << "vector v3 y : " << v3.y << std::endl; } 

when print aso.x, y gives me 4 , 5. want add both v1 , v2; meaning x of v1 , v2, , y of v1 , v2. then, pass vectors object , return object.

how accomplish that, given have above?

you meant

vectors operator+(const vectors& aso) {         vectors brandnew;         std::cout << "aso x " << aso.x << std::endl;         std::cout << "aso y " << aso.y << std::endl;         brandnew.x = x + aso.x;         brandnew.y = y + aso.y;         return (brandnew);     }; 

or

vectors operator+(const vectors& aso) {     vectors brandnew(x + aso.x, y + aso.y);     std::cout << "aso x " << aso.x << std::endl;     std::cout << "aso y " << aso.y << std::endl;     return (brandnew); }; 

---

as comment

but if there three.

chain operators like

int main() {     vectors v1(2,3);     vectors v2(4,5);     vectors v3(7,11);     vectors v4;     v4 = v1 + v2 + v3;      std::cout << "vector v4 x : " << v4.x << std::endl;     std::cout << "vector v4 x : " << v4.y << std::endl; } 

see live demo