c - passing a structure for comparison -

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struct sign_in {     char password[max_name_len+1];//the password each player     char name[max_name_len+1];//name of people can sign in }    //prototype int compare_names(char*, char*, struct sign_in*);   int compare_names(char*pname,char*ppasscode,struct sign_in *var) {     int icomparison = 1;     int flag = 1;     int icomparison2 = 1;     int = 0;      (i=0;i<6;i++)     {         printf("%s \t %s ", var[0].name,pname );         if(icomparison != 0)         {             icomparison = strcmp(pname,var[i].name);             i++;         }         if(icomparison2 != 0)         {             icomparison2 = strcmp(ppasscode,var[i].password);             i++;         }          printf("%d", icomparison);         printf("%d", icomparison2);     } }

i have updated code , attempted take account many of aspects guys have recommended , news runs now. bad news still attempts print random jargon don't understand, it's collection of symbols usually. structure function compares against has 6 members that's reason parameters on first loop.

the code you've presented cornucopia of sloppyness. when programming, that's not ok.

  • you forgot closing curly braces struct sign_in definition , compare_names() function definition
  • you did not initialize icomparisson value. flag initialized, icomparisson not. also, it's misspelled!
  • don't use printf() user-input format string, there % in there. @ least printf("%s", pname). , want \n in there too.
  • strcmp() might return -1 mean pname sorts before var[i].name (and differs of course), while(icomparisson == 1) not want
  • you need know length of var array , stop loop before run off end
  • strcmp() takes strings, pointers. when call strcmp(*pname, ...) you're dereferencing pname "pointer char" "char". it's getting first character pname string, , putting character value pointer-to-character value expected. not good. situation var[i].name bit more complicated because name array, rid of star, it's not needed either.
  • the second while () loop loop forever if ipasscode not match, want if ()
  • in problem description omit closing backtick after *var[i].password , closing double-quote after "invalid type argument of unaray", , mangled compiler error message well. makes harder understand wrote , went wrong.
  • the ipasscode == var[i].password looks fine. seems rather isn't code had problem with, due other ridiculous problems in sample ...

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